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From: Arno Welzel <usenet@arnowelzel.de>
Newsgroups: comp.lang.php
Subject: Re: Implied cast differs from explicit cast
Date: Tue, 17 Jan 2012 06:59:10 +0100
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Jerry Stuckle, 2012-01-16 14:45:

> On 1/16/2012 8:28 AM, The Natural Philosopher wrote:
>> lb wrote:
>>> jstucklex@attglobal.net wrote:
>>>> ...
>>>> No, it is not. '0x12' is a hex number, not an integer. (int)'0x12'
>>>> converts this correctly to 0.
>>
>> Looks like Jerry doesn't know what an integer is either.
>>
>> A hex number of course *is* an integer, unless its a hex representation
>> of floating point.
>>
>> Killfile the prat like I have.
>>
>>
> 
> 0x12 is not an integer.  It is a hexadecimal value.

No, 0x12 (and *not* "0x12") is the hexadecimal *representation* of the
value 18. There is no thing like "hexadecimal value" and "0x12" is a
*string* and not a number at all.

In fact PHP only knows to types of numbers: integers and floating point.
There is no "hexadecimal" data type.

> It can have the same bit pattern as an integer - but it can also have
> the same bit pattern as a character (Ctrl-R, to be exact).

Which also applies to the value 18 - this can also be the value of a
character.

Example:

<?php
$a = 0x12;

print $a;
?>

Result:

Value of $a: 18, type of $a: integer

So you see 0x12 *is* an integer.

Of course "0x12" (including the quotes) is a string and *converting* the
string to a number may need attention to the representation of the
number within the string.


-- 
Arno Welzel
http://arnowelzel.de
http://de-rec-fahrrad.de