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Message-ID: <4900575.IOLIoYm6Jl@PointedEars.de>
From: Thomas 'PointedEars' Lahn <PointedEars@web.de>
Reply-To: Thomas 'PointedEars' Lahn <php@PointedEars.de>
Organization: PointedEars Software (PES)
Date: Sat, 15 Mar 2014 23:14:17 +0100
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Subject: Re: Filling an array with random input doesn't quite work
Newsgroups: comp.lang.php
References: <12lin35i3xsev.abk024ld5l8l.dlg@40tude.net> <CYIUu.12650$%o4.7530@fx09.iad> <2311625.YxiY5vK2W4@PointedEars.de> <0.6b9d1a51aaf973162356.20140315213216GMT.8761nf5esf.fsf@bsb.me.uk>
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Ben Bacarisse wrote:

> Thomas 'PointedEars' Lahn <PointedEars@web.de> writes:
>> Daniel Pitts wrote:
>>> for ($x = 1; $x < 40; ++$x) {
>>>    $ayr[$x] = rand(60, 69);
>>> }
>>> 
>>> So much simpler, more efficient, and actually correct.
>>
>> No, this will produce an array of only 39 elements, assuming there was
>> not already one.  This can be easily fixed, of course.
>>
>> Still,
>>
>>   $keys = range(1, 40);
>>   $ayr = array_combine($keys, array_map(function () {
>>     return rand(60, 69);
>>   }, $keys)));
>>
>> is much more elegant :)
> 
> Yes, but it's a shame about the extra ')'.

Ah, yes, no idea how that got in there.  Should have been

  $keys = range(1, 40);
  $ayr = array_combine($keys, array_map(function () {
    return rand(60, 69);
  }, $keys));

> I think
> 
>   $ayr = array_map(function () { return rand(60, 69); },
>                    array_fill(1, 40, null));
> 
> is a little simpler.

ACK.  Actually, I had experimented with array_fill() but, strangely enough, 
I overlooked this possibility.  (I had posted something similar with regard 
to letters not long ago.)


PointedEars
-- 
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