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From: Ben Bacarisse <ben.usenet@bsb.me.uk>
Newsgroups: comp.lang.javascript
Subject: Re: Handling multiple results from combinations
Date: Tue, 24 Jan 2017 14:22:27 +0000
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Andrew Poulos <ap_prog@hotmail.com> writes:

> Say there are 10 options that can be selected in any order and each
> combination produces a different result. Is there some way to approach
> judging the options to choose the result without having such a tree
> full of IF statements:
>
> if (a && b && c...) {
>   //
> } else if (a && b && !c...) {
>   //
> } else if (a && !b && !c...) {
>   //
> } else if (!a && b && !c...) {
>   //
> } else if (!a && !b && !c...) {
> ...
>
> Currently I'm working on an elearning question where there are
> multiple options and different combinations of selected options gives
> different feedback.

A couple of extra points...

It's probably better to have the answers in an array rather than in
named variables.

You don't need to use a numeric value based on 0/1 bit to generate a key
for the response.  You can also use a string.  For example

  var response = [ true, false, false, true, false, true ];
  response.map((r, i) => r ? i.toString()+'/' : '').join('');

will give '0/3/5/'.  If you choose the right string, it might be easier
when associating the result with the responses.

<snip>
-- 
Ben.