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Message-ID: <1934720.aqSPkdTlGX@PointedEars.de>
From: Thomas 'PointedEars' Lahn <PointedEars@web.de>
Reply-To: Thomas 'PointedEars' Lahn <cljs@PointedEars.de>
Organization: PointedEars Software (PES)
Date: Wed, 25 Jan 2012 19:39:02 +0100
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Subject: Re: Initialize multi-dimensional array
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Andreas Bergmaier wrote:

> Archos schrieb:
>> I want to initialize a multidimensional array to a determined value
>>
>> I can do:
>> var a2 = new Array(2); for (var i0=0; i0<2; i0++){ a2[i0]=new
>> Array(4); }
>> for (var i0=0; i0<2; i0++){ for (var i1=0; i1<4; i1++){ a2[i0]
>> [i1]=1; }}
>>
>> or shorter:
>> var a2 = new Array(2); for (var i0=0; i0<2; i0++){ a2[i0]=new
>> Array(4); for (var i1=0; i1<4; i1++){ a2[i0][i1]=1; }}
>>
>> But is there any another way to do it shorter? Without use `var a2 =
>> [[1,1,1,1], [1,1,1,1]]`
> 
> What do you mean with "shorter"? Less code? Faster execution? If you
> don't want to use array literals, there will always be two loops:

No.
 
> var a=[];for(var i=0;i<2;i++){a[i]=[];for(var j=0;j<4;j++)a[i][j]=1;}
        ^^                           ^^
JFYI: You are using two Array literals here, of course.
 
> There might be tricky expressions with less code, but you don't really
> want them.

A matter of opinion.  Surely

  var a = [];
  a.length = 5;
  a = a.join("1").split("").map(function (el) { return +el; });
  a = [a, a.slice()];

is a more elegant solution to this problem.


PointedEars
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