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From: Knute Johnson <eternal@knutejohnson.com>
Newsgroups: comp.lang.java.programmer
Subject: Re: Accessing super method from inner class?
Date: Thu, 13 Nov 2014 10:01:50 -0800
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On 11/12/2014 18:54, Jeff Higgins wrote:
> On 11/12/2014 08:40 PM, Knute Johnson wrote:
>> I've got some code where I am wrapping all the calls to
>> JTextArea.append() in EventQueue.invokeLater().  So I thought I would
>> just extend JTextArea but what I thought was obvious isn't.
>>
>> import java.awt.*;
>> import javax.swing.*;
>>
>> public class KTextArea extends JTextArea {
>>      public KTextArea(String text) {
>>          super(text);
>>      }
>>
>>      public void append(final String str) {
>>          EventQueue.invokeLater(new Runnable() {
>>              public void run() {
>>                  KTextArea.this.super.append(str);
>
> In this context, this means your new Runnable, super means Object,
> and KTextArea.super means JTextArea, and KTextArea.this is undefined.
>
> I think.
>

I think I've answered my own question, from the JLS;

"15.12
Method Invocation Expressions
EXPRESSIONS
500

Suppose that a field access expression T.super.f appears within class C, 
and the immediate superclass of the class denoted by T is a class whose 
fully qualified name is S. If f in S is accessible from C , then 
T.super.f is treated as if it had been the expression this.f in the body 
of class S. Otherwise, a compile-time error occurs."

I'm not sure if that is what you are saying but I think so.  I thought 
that the 'this' was needed to reach the instance but it appears as 
though Class.super.field implies SuperClass.this.field.  I'm curious how 
this is going to work with static fields :-).

Thanks for taking the time to answer.

-- 

Knute Johnson