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From: Jeff Higgins <jeff@invalid.invalid>
Newsgroups: comp.lang.java.programmer
Subject: Re: in1To10
Date: Sat, 09 Aug 2014 15:58:08 -0400
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On 08/09/2014 03:12 PM, cdalten@gmail.com wrote:
> from the url
>
> http://codingbat.com/prob/p137365
>
> The problem states: "Given a number n, return true if n is in the range 1..10, inclusive. Unless "outsideMode" is true, in which case return true if the number is less or equal to 1, or greater or equal to 10."
>
> Here is what I came up with...
>
> public class In1to10 {
> 	static boolean in1To10(int n, boolean outsideMode) {
> 		
> 		if (outsideMode == false){
> 			if (n >= 1 && n <=10) {
> 				return true;
> 			}
> 		} else if (outsideMode == true){
> 			if (n <=1 || n >=10) {
> 				return true;
> 			}
> 		}
> 		
> 		return false;
> 	}
> 	public static void main(String[] args) {
> 		System.out.println(in1To10(5, false)); //true
> 		System.out.println(in1To10(11, false)); //false
> 		System.out.println(in1To10(11, true)); //true
> 	}//end main
> }
>
>
> Now upon googling the solutions, I saw some people use
> if(outsideMode == false)
> if(outsideMode == true)
>
> instead of using if(outsideMode == false)/else(outsideMode == true).
>
> Would both catch all the cases? If not, which one would?

The Java Tutorial explains quite well the difference between
if-then and if-then-else statements. Also what happens when
a branching statement is encountered.
<http://docs.oracle.com/javase/tutorial/java/nutsandbolts/if.html>
<http://docs.oracle.com/javase/tutorial/java/nutsandbolts/branch.html>

>
> Chad
>