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From: Stanimir Stamenkov <s7an10@netscape.net>
Newsgroups: comp.lang.java.programmer
Subject: Re: [LONG] java.net.URI encoding weirdness
Date: Tue, 06 May 2014 22:24:13 +0300
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Tue, 06 May 2014 10:26:56 +0300, /markspace/:
> On 5/6/2014 12:26 AM, Stanimir Stamenkov wrote:
>
>>      public static void main(String[] args) throws Exception {
>>          URI u = URI.create("http://server1/path"
>>                  + "?param%3D1=value%261&param%3F2=value%232"
>                            ^^^       ^^^       ^^^       ^^^
>>                  + "#fragment");
>
>> Note how the 'query' is wrong now.
>
> Doesn't each % above indicate an encoded value, or are you referring
> to something else?

You're missing I'm using further:

         URI v = new URI(u.getScheme(),
                         u.getUserInfo(),
                         "server2",
                         u.getPort(),
                         u.getPath(),
                         u.getQuery(),
                         u.getFragment());

The 'query' property value is already decoded.

> I'm not sure we're not talking cross purposes here.
>
>          URI u = URI.create( decode("http://server1/path"
>                  + "?param%3D1=value%261&param%3F2=value%242"
>                  + "#fragment"));
>          System.out.println(u.toASCIIString());
>
> run:
> http://server1/path?param=1=value&1&param?2=value$2#fragment
> BUILD SUCCESSFUL (total time: 1 second)

The URI.create(String) and the URI(String) constructor perform 
complete parsing, and they are working fine.  Note, after decoding 
the result of your example is already wrong, different from the 
original URI:

http://server1/path?param%3D1=value%261&param%3F2=value%242#fragment

There are two parameters (decoded names):

param=1
param?2

and their (decoded) values are:

value&1
value#2

What would be the query parameters in your result:

http://server1/path?param=1=value&1&param?2=value$2#fragment

?

-- 
Stanimir