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From: Daniele Futtorovic <da.futt.news@laposte-dot-net.invalid>
Newsgroups: comp.lang.java.programmer
Subject: Re: How to convert image into Hex 2 Dimensional Array?
Date: Thu, 09 May 2013 04:09:11 +0200
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On 09/05/2013 04:03, Arne Vajhøj allegedly wrote:
> On 5/8/2013 9:59 PM, Arne Vajhøj wrote:
>> On 5/8/2013 9:45 PM, Eric Sosman wrote:
>>> On 5/8/2013 9:04 PM, Arne Vajhøj wrote:
>>>> On 5/8/2013 9:57 AM, lipska the kat wrote:
>>>>> [...] the following two lines are
>>>>> logically equivalent.
>>>>>
>>>>> 1. Byte[][] bytes = new Byte[width][height];
>>>>> 2. byte[][] bytes = new byte[width][length]
>>>>
>>>> Not at all.
>>>>
>>>> You will eventually end up with 1+width*height and 1 objects
>>>> respectively.
>>>
>>>      No; both will generate 1+width objects:
>>>
>>>      - One array containing `width' references to other arrays,
>>>
>>>      - `width' arrays containing `height' bytes or Byte
>>>        references.
>>>
>>>      A *really* stupid coder might use Byte[][] *and* populate
>>> the arrays with `new Byte(value)' repeated `width*height' times;
>>> that would produce `1 + width + width*height' objects in all.
>>> Autoboxers would be unlikely to enter that particular trap --
>>> but even so, a four- to eight-fold memory bloat is not to be
>>> sneezed at.
>>
>> Ooops.
>>
>> 1+width+width*height and 1+width objects.
>>
>> I would still expect the byte version to end up
>> with width*height Byte objects.
>>
>> If there are no null and no reused objects, then
>> I can not see how that can be avoided.
> 
> Are you saying that Java will intern so aggressively
> that there will be reused objects?

Autoboxing will you Byte#valueOf, which returns pooled instances.

-- 
DF.