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From: Mike Amling <mamling@chaff.us>
Newsgroups: comp.lang.java.programmer
Subject: Re: [LONG] java.net.URI encoding weirdness
Date: Mon, 05 May 2014 11:43:04 -0500
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On 5/5/14 11:37 AM, Mike Amling wrote:
> On 5/5/14 8:11 AM, Stanimir Stamenkov wrote:
>> This is a long time observation but I wanted to summarize it and give
>> heads up to ones which might not have encountered it, yet.
>> ...
>> Now, I expect the URI(scheme, authority, path, query, fragment)
>> constructor would need a raw 'authority' value as it gets parsed into
>> 'userInfo', 'host' and 'port' components/properties:
>>
>> public class URITest2 {
>>
>>      public static void main(String[] args) throws Exception {
>>          URI u = URI.create("http://user%40domain@server1:8080"
>>                             + "/path?param=value#fragment");
>>          System.out.println(u.toASCIIString());
>>
>>          URI v = new URI(u.getScheme(),
>>                          u.getAuthority(),
>>                          "/htap",
>>                          u.getQuery(),
>>                          u.getFragment());
>>          System.out.println(v.toASCIIString());
>>
>>          URI w = new URI(u.getScheme(),
>>                          u.getRawAuthority(),
>>                          "/htap",
>>                          u.getQuery(),
>>                          u.getFragment());
>>          System.out.println(w.toASCIIString());
>>      }
>>
>> }
>>
>> The output:
>>
>> http://user%40domain@server1:8080/path?param=value#fragment
>> http://user@domain@server1:8080/htap?param=value#fragment
>> http://user%2540domain@server1:8080/htap?param=value#fragment
>>
>> shows there's no way to re-construct a correct URI using it.
>>
>> ... TL;DR
>
> Looks like you need
>
> URI v = new URI(
>   u.getScheme(),
>   u.getAuthority().someKindOfEncodeFunction(),
>   "/htap",
>   u.getQuery(),
>   u.getFragment());

  Oh, no, that won't work, either. Sorry.

Mike Amling
--
T29wcw==