Path: csiph.com!usenet.pasdenom.info!weretis.net!feeder1.news.weretis.net!news.swapon.de!fu-berlin.de!uni-berlin.de!individual.net!not-for-mail From: Robert Klemme Newsgroups: comp.lang.java.programmer Subject: Re: unnecessary code in Oracle example? Date: Wed, 09 Oct 2013 21:11:21 +0200 Lines: 102 Message-ID: References: Mime-Version: 1.0 Content-Type: text/plain; charset=ISO-8859-1; format=flowed Content-Transfer-Encoding: 7bit X-Trace: individual.net 04t+zYL9f9LqScg/AJB+2g3NnEUL+6APrUnTne0udHTQaE8+s= Cancel-Lock: sha1:/poAM/tsHPYucnmiqS6xW0th7vs= User-Agent: Mozilla/5.0 (X11; Linux i686; rv:24.0) Gecko/20100101 Thunderbird/24.0 In-Reply-To: Xref: csiph.com comp.lang.java.programmer:26258 On 10/09/2013 08:19 PM, Daniel Pitts wrote: > On 10/9/13 9:38 AM, Jim Janney wrote: >> I'm reading up on Java 7's try-with-resource statement and looking at >> the tutorial at >> >> http://docs.oracle.com/javase/tutorial/essential/exceptions/tryResourceClose.html >> >> >> which includes the following code: >> >>> static String readFirstLineFromFileWithFinallyBlock(String path) >>> throws IOException { >>> BufferedReader br = new BufferedReader(new FileReader(path)); >>> try { >>> return br.readLine(); >>> } finally { >>> if (br != null) br.close(); >>> } >>> } >> >> As a matter of habit, I always write that pattern as >> >> >>> static String readFirstLineFromFileWithFinallyBlock(String path) >>> throws >>> IOException { >>> BufferedReader br = new BufferedReader(new FileReader(path)); >>> try { >>> return br.readLine(); >>> } finally { >>> br.close(); >>> } >>> } >> >> on the theory that if you reach that point br can never be null, so the >> test is both redundant and confusing. On the other hand, I might be >> wrong. Is there a reason to test for null in the finally block? If you declare the variable "final" then there is no reason. The way you showed it "br" can actually become null. > You are correct for this case, the other case comes from a block which > uses multiple resources. > > MyResource r1 = null; > MyResource r2 = null; > > try { > r1 = openResource1(); > r2 = openResource2(); > } finally { > if (r1 != null) r1.close(); > if (r2 != null) r2.close(); > } > > Of course, some close() methods can throw, which could break this idiom > too. The proper (i.e. robust) way to do it would be to spend one try finally block per resource. That may not be the prettiest of idioms because of the indentation but it's robust. > This is one reason why C++ forbids destructors from throwing. Does it? $ cat -n x.cxx 1 2 3 #include 4 5 class Ex { 6 }; 7 8 class Foo { 9 public: 10 ~Foo() throw (Ex) { 11 std::cout << "destructor" << std::endl; 12 throw Ex(); 13 } 14 }; 15 16 int main() { 17 try { 18 Foo f; 19 std::cout << "foo" << std::endl; 20 } 21 catch (Ex e) { 22 std::cout << "caught" << std::endl; 23 } 24 25 return 0; 26 } 27 robert@fussel:~$ g++ x.cxx && ./a.out foo destructor caught Cheers robert