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From: "Eric Sosman" <eric.sosman@1:261/38.remove-i5b-this>
Newsgroups: comp.lang.java.programmer
Subject: Re: Has Android different floats?
Date: Sun, 24 Jun 2018 17:28:58 -0500
Organization: Agency News - Dunedin, New Zealand
Message-ID: <5B329ADB.1167.ucljprogr@castlerockbbs.com>
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To: bursejan
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  To: bursejan
From: "Eric Sosman" <eric.sosman@1:261/38.remove-101j-this>

  To: bursejan
From: Eric Sosman <esosman@comcast-dot-net.invalid>

On 6/24/2018 4:35 PM, bursejan@gmail.com wrote:
> The test code would be:
>
>          for (int i=22; i<25; i++) {
>             System.out.println("Math.pow(10,"+i+")="+Math.pow(10,i));
>          }
>
> The result (without strictfp modifier to main()) is:
>
>     Math.pow(10,22)=1.0E22
>     Math.pow(10,23)=1.0000000000000001E23
>     Math.pow(10,24)=1.0E24
>
> The result (with strictfp modifier to main()) is:
>
>     Math.pow(10,22)=1.0E22
>     Math.pow(10,23)=1.0000000000000001E23
>     Math.pow(10,24)=1.0E24
>
> Because invoking Math.pow() is not a basic operator +, *, /, etc..

     Have you tried using StrictMath.pow() instead of Math.pow()?
It is certainly possible that the Math implementations are different on
different platforms -- at least, the Javadoc seems to allow such freedom:

        "[...] Code generators are encouraged to use platform-specific
        native libraries or microprocessor instructions, where
        available, to provide higher-performance implementations of Math
        methods. [...]"

It's my understanding, though, that StrictMath implementations on all platforms
 are supposed to agree exactly.

--
esosman@comcast-dot-net.invalid
Nine hundred forty-one days to go.

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