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From: Keith Thompson <kst-u@mib.org>
Newsgroups: comp.lang.c
Subject: Re: Access structure members via pointer to an array of structures
Date: Sun, 22 Jan 2017 07:50:42 -0800
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Gareth Owen <gwowen@gmail.com> writes:
> Keith Thompson <kst-u@mib.org> writes:
>> Why would you tell someone trying to learn C about "array pointer
>> equivalence"?  Arrays and pointers are not equivalent.
>
> They are occasionally

Nope.

> f(char *ptr){
>   printf("%s - %u\n",ptr,(unsigned)sizeof(ptr));
> }
>
> f(char arr[10]){
>   printf("%s - %u\n",arr,(unsigned)sizeof(arr));
> }

arr is a pointer parameter that happens to be defined using array
syntax.  A parameter defined with an array type is adjusted to have a
pointer type.  The parameter definitions `char *ptr` and `char ptr[]`
are equivalent, but calling that "array pointer equivalence" is
misleading.

[...]

-- 
Keith Thompson (The_Other_Keith) kst-u@mib.org  <http://www.ghoti.net/~kst>
Working, but not speaking, for JetHead Development, Inc.
"We must do something.  This is something.  Therefore, we must do this."
    -- Antony Jay and Jonathan Lynn, "Yes Minister"