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From: Keith Thompson <kst-u@mib.org>
Newsgroups: comp.lang.c
Subject: Re: C Programming Tutorial on Youtube
Date: Sat, 15 Oct 2016 12:12:06 -0700
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Richard Damon <Richard@Damon-Family.org> writes:
> On 10/11/16 9:55 PM, Keith Thompson wrote:
>> Malcolm McLean <malcolm.mclean5@btinternet.com> writes:
>>> int buff[1024];
>>>
>>> buff is a constant pointer to a buffer (which C mis-terms an "array")
>>> which contains enough space for 1024 integers. Except there's a little
>>> syntactical quirk. But that can be ignored for now.
>>
>> If you're trying to demonstrate the idea of being deliberate misleading,
>> well done.
>
> IF you want a constant pointer to a 'buffer' of ints:
>
> int buffer[1024][
>
> int * const pointer = buffer;
>
> pointer now IS a constant pointer to the array buffer. accessable int by 
> int.

Warning: Pedantic quibbling follows.

Strictly speaking `pointer` is const (read-only), not constant
(evaluated at compile time).

If you want to access the elements of `buffer`, then defining a
pointer to its element type is the way to go.  If you literally
want a pointer to the buffer (assuming that "buffer" means "array
object"), you need a pointer to the array type:

    const int (*p)[1000] = &buffer;

but that happens to be less useful.

-- 
Keith Thompson (The_Other_Keith) kst-u@mib.org  <http://www.ghoti.net/~kst>
Working, but not speaking, for JetHead Development, Inc.
"We must do something.  This is something.  Therefore, we must do this."
    -- Antony Jay and Jonathan Lynn, "Yes Minister"