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From: Keith Thompson <kst-u@mib.org>
Newsgroups: comp.lang.c
Subject: Re: How to get a character consisting of multiple bytes into a string literal?
Date: Sat, 24 Oct 2015 13:44:49 -0700
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Malcolm McLean <malcolm.mclean5@btinternet.com> writes:
> On Saturday, October 24, 2015 at 6:18:56 PM UTC+1, Philipp Klaus Krause wrote:
>> Assuming my implementation supports the basic source character set, how
>> can I create a string literal that contains multibyte character
>> consisting of multiple bytes?
>> 
> Depends how you want to pass the data about.
>
> You can use the L prefix L"Wide chars"; to create a 16-bit string
> literal.

A string literal prefixed with L represent a sequence of wchar_t
elements.  wchar_t is typically 16 bits on Windows, but 32 bits on
Unix-like systems.

>          Or you use use UTF-8 and write char *str = "utf-8 is ascii
> with extended characters like aleph (\xe2\x84\xb5)";

Or, if your compiler supports it, u8"..." is a UTF-8 string literal,
u"..." represents a sequence of char16_t, and U"..." represents a
sequence of char32_t.  These are new in C11.

> The second method is OK for a few embedded non-English characters,
> but not human-maintainable for flowing text, so realistically you'll
> need a tool to generate the literals.

-- 
Keith Thompson (The_Other_Keith) kst-u@mib.org  <http://www.ghoti.net/~kst>
Working, but not speaking, for JetHead Development, Inc.
"We must do something.  This is something.  Therefore, we must do this."
    -- Antony Jay and Jonathan Lynn, "Yes Minister"