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Date: Sat, 28 Apr 2012 14:59:31 -0400
From: pete <pfiland@mindspring.com>
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Subject: Re: The question regarding type of pointers
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Xref: csiph.com comp.lang.c:20025

somenath wrote:
 
> Now let us focus on the two dimensional array.
> ==========================================================
> Suppose we have the following declaration
>  int  ar[3][3];

> Question=> What is sizeof( ar[3])?
> 
> So what is ar[3]? ar[3] contains the pointer 

No, ar[3] doesn't contain any pointer.

ar[3] is an expression of type array of three int.


/* BEGIN new.c */

#include <stdio.h>

int 
main(void)
{
    char ar[3][7];

    printf("sizeof ar[3] is %u\n.", (unsigned)sizeof ar[3]);
    return 0;
}

/* END new.c */


-- 
pete