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NNTP-Posting-Date: Thu, 05 Apr 2012 08:03:05 -0500
Message-ID: <4F7D9807.1D82@mindspring.com>
Date: Thu, 05 Apr 2012 09:03:03 -0400
From: pete <pfiland@mindspring.com>
Reply-To: pfiland@mindspring.com
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Subject: Re: Odd benchmark behavior
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Xref: csiph.com comp.lang.c:19359

io_x wrote:
> 
> "pete" <pfiland@mindspring.com> ha scritto nel messaggio
> news:4F7D788E.45B9@mindspring.com...
> > io_x wrote:
> >>
> >> "pete" <pfiland@mindspring.com> ha scritto nel messaggio
> >> news:4F727C20.5A49@mindspring.com...
> >> > io_x wrote:
> >> >>
> >> >> "io_x" <a@b.c.invalid> ha scritto nel messaggio
> >> >> news:4f71688a$0$1383$4fafbaef@reader2.news.tin.it...
> >> >>
> >> >> there is someone that know if  (unsigned) sqrt(9.0) can be
> >> >> follow the C standard the unsigned 2???
> >> >> Thank you
> >> >
> >> > You could do it this way instead:
> >> >
> >> > la:
> >> >    v = p;
> >> >    for (i = ((1 == v) + v) / 2; v > i; i = (p / v + v) / 2) {
> >> >        v = i;
> >> >    }

> > This is the code that you wrote:
> >    #define  u32  uint32_t
> >    u32    i, p, cnt, v;
> > There are no float numbers in that code.

> why this print the wrong result??

> {double  v, i;

That print the wrong result 
because you changed the code to make it wrong.

You already defined (v), (p) and (i) to be all integes,
in your function 
u32  FindNPrime(u32  pos)

The code that I wote, is supposed to be used by you
to replace the line of code that you wrote
at the label la:

la: r=p; v=sqrt(r);

After the line with the lable la:
 What you want is for (v) to be equal to the greatest integer
 with a value less than or equal to the square root of (p).

My suggestion was for you to replace the floating point math
in your FindNPrime function with integer math.

-- 
pete