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NNTP-Posting-Date: Mon, 27 Jun 2011 00:33:21 -0500
Message-ID: <4E081602.7842@mindspring.com>
Date: Mon, 27 Jun 2011 01:32:50 -0400
From: pete <pfiland@mindspring.com>
Reply-To: pfiland@mindspring.com
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Subject: Re: what about my array type?
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io_x wrote:
> 
> "Barry Schwarz" <schwarzb@dqel.com> ha scritto nel messaggio
> news:t7mf07d716olfv14kqcem0dalkhksue6po@4ax.com...
> > On Sun, 26 Jun 2011 19:08:36 +0200, "io_x" <a@b.c.invalid> wrote:

> >>when someone has "a=3"
> >>than is possible to have &a, but why not &3?
> >>where &3 means the place in the memory [address]
> >>where there is stored the value 3
> >
> > What makes you think that the value 3 must be stored somewhere in
> > memory?
> 
> because here is in the memory, it could be in section data
> can be in section text, for example the instruction
> mov eax, 3
> has in the code section, in the space reserved for store the memory
> for this instruction, has the number 3
> there is one addres in the executable that contai 3

That just happens to be that way on the C implementation
that you are using right now.

There's no rule in C which specifies how
   a = 3;
must be translated.

   a = 3;
only means that after the statement is executed,
that (a) will have a value of 3.

If the statement were
   a = 0;
instead, then it might be translated as a (clear) 
instruction, rather than as a (mov) instuction.


-- 
pete