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NNTP-Posting-Date: Wed, 11 May 2011 07:10:31 -0500
Message-ID: <4DCA7CBA.5F7A@mindspring.com>
Date: Wed, 11 May 2011 08:10:34 -0400
From: pete <pfiland@mindspring.com>
Reply-To: pfiland@mindspring.com
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Subject: Re: Passing an integer to a function that accepts a void pointer
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Xref: x330-a1.tempe.blueboxinc.net comp.lang.c:3745

Tom St Denis wrote:
> 
> On May 11, 6:01 am, pozz <pozzu...@gmail.com> wrote:
> > What do you think about this code?
> >
> > int foo(const void *Args) {
> >   printf("%d\n", (const int)Args);
> >   return 0;
> >
> > }
> >
> > int main(int argc, char *argv[]) {
> >   foo((void *)10);
> >   return 0;
> >
> > }
> >
> > It seems work and it should be nice if it is a sufficient portable way
> > to pass integers as pointers.
> >
> > Why don't I declare foo() to directly accept int? Because it is a
> > callback of a library I can't change and the prototype of the callback
> > is well defined by the library to accept void pointer.
> 
> Why not just do this
> 
> int bar = 10;
> foo(&bar);
> 
> And inside foo do
> 
> printf("%d\n", *((int *)Args));
> 
> That way the program is actually portable.

That's what I was thinking too.

-- 
pete