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From: Tim Rentsch
Newsgroups: comp.lang.c++
Subject: Re: Has "stack overflow" specified behavior?
Date: Mon, 13 Dec 2021 14:16:05 -0800
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Paavo Helde writes:
> 12.12.2021 10:42 wij kirjutas:
>
>> void t() {
>> int a;
>> ++a;
>> t();
>> };
>>
>> int main()
>> {
>> t();
>> }
>>
>> ---
>> Has "stack overflow" specified behavior?
>
> No. Stack overflow is arguably the least specified behavior of them
> all. The stack size is extremely limited (few MB), compared to the
> RAM amounts current computers have (tens of GB). There is no
> standard-defined way to detect stack overflow, not to speak about
> handling it. That's one reason why using stack-allocated things
> like std::array needs special care, especially when writing
> libraries (which need to execute in a stack of unknown size and
> fill-up).
>
> There are some implementation-defined ways though to survive stack
> overflows, but it's not so easy. You cannot continue the program if
> there is no more stack space, so the only way is to throw an
> exception. Alas, there is no "throw" statement in the code, so this
> would be an "asynchronous" exception appearing at a pretty random
> place in the code, meaning that the compiler must cope with such
> exceptions, which may easily slow down the whole program (witness
> the /EHa compiler option in MSVC).
>
> BTW, your example code is not guaranteed to cause stack overflow, it
> might go into an infinite loop instead because of tail recursion, or
> become a zero op by optimizing the whole t() function away, either
> as UB or as a code with no effect.
It's important to distinguish the two realms of abstract machine
and actual machine. In the abstract machine, the program shown
above (after fixing the problem of reading an uninitialized
variable) does have a well-defined specification, and the program
as a whole has defined behavior. Whether a program has defined
behavior or undefined behavior is determined solely by what goes
on in the abstract machine (which may depend on values read from
a file or other input device, etc, but still the question is to
be answered considering only what happens in the abstract
machine, with reference to any actual machine). Everything the
program does has a well-defined specification, and so the program
has only defined behavior, and no undefined behavior.
In an actual machine, an implementation is obliged to carry out
the abstract semantics only to the extent that the execution
does not exceed the implementation's "resource limits", which
might be anything at all, including stack space. Once such a
resource limit is exceeded, the implementation has no further
obligations, and may abort, or whatever. But that isn't the
same as undefined behavior, which depends solely on what the
standard says about operations in the abstract machine.