Path: csiph.com!xmission!usenet.blueworldhosting.com!feeder01.blueworldhosting.com!border2.nntp.dca1.giganews.com!border1.nntp.dca1.giganews.com!nntp.giganews.com!news.iecc.com!.POSTED.news.iecc.com!nerds-end From: "SLK Mail" Newsgroups: comp.compilers Subject: =?utf-8?B?T1Q6IFByb29mIHRoYXQgUOKJoE5Q?= Date: Tue, 09 Aug 2016 12:24:46 -0800 Organization: SLK Systems Lines: 12 Sender: news@iecc.com Approved: comp.compilers@iecc.com Message-ID: <16-08-003@comp.compilers> Mime-Version: 1.0 Content-Type: text/plain; charset=utf-8; format=flowed; delsp=yes Content-Transfer-Encoding: 8bit Injection-Info: miucha.iecc.com; posting-host="news.iecc.com:2001:470:1f07:1126:0:676f:7373:6970"; logging-data="82445"; mail-complaints-to="abuse@iecc.com" Keywords: theory Posted-Date: 11 Aug 2016 17:05:54 EDT X-submission-address: compilers@iecc.com X-moderator-address: compilers-request@iecc.com X-FAQ-and-archives: http://compilers.iecc.com Xref: csiph.com comp.compilers:1725 A constructive proof is given to show that the complement of non-SLL(k) testing is not in NP. The proof focuses on the verification step of determining membership in NP. An instance of the problem is shown to generate an intractable number of items that must be verified, making the nondeterministic solution unverifiable in polynomial time. Since non-SLL(k) testing is well known to be NP-complete, the complement of an NP-complete problem is not in NP, so it follows that NPb coNP. Here the abreviation SLL(k) means strong LL(k), not its original usage for simple LL(k). http://www.slkpg.com/NPcoNP.html