Path: csiph.com!eternal-september.org!feeder.eternal-september.org!reader02.eternal-september.org!.POSTED!not-for-mail From: Don Kuenz Newsgroups: sci.electronics.design Subject: Re: AC switch fault current philosophy Date: Wed, 3 Jan 2018 17:57:27 -0000 (UTC) Organization: A noiseless patient Spider Lines: 24 Distribution: world Message-ID: <20180103a@crcomp.net> References: <20171228b@crcomp.net> Injection-Date: Wed, 3 Jan 2018 17:57:27 -0000 (UTC) Injection-Info: reader02.eternal-september.org; posting-host="cbddec1ca58d499ea78b09163b8944b3"; logging-data="13693"; mail-complaints-to="abuse@eternal-september.org"; posting-account="U2FsdGVkX18qewoIl9bg4hSgFJ2mgp2f" Cancel-Lock: sha1:TMbawyUe4/ejVt6vADSJdONu/C0= Xref: csiph.com sci.electronics.design:490167 Tim Williams wrote: > "Don Kuenz" wrote in message news:20171228b@crcomp.net... >> You might limit the current and trip the mains breaker to cope with the >> short. That way you simultaneously protect the shorted device and send >> users a dramatic message that something's wrong. > > How does that work? > > If you have a shunt coil to trip the breaker separately (like a lot of > UL1077 breakers do, or the guts of a GFCI receptacle), you can open the > circuit without drawing fault current. Though that still won't act fast > enough to save a transistor (not without a switching mechanism like I > described, anyway). Is it possible to separate the current limit functionality from the mains breaker trip? Limit the current first and always, sense an over current state, and then leisurely use a low voltage to trip the mains breaker a few cycles later? Thank you, -- Don Kuenz, KB7RPU