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Date: Thu, 16 Mar 2017 12:09:55 +0100
From: rePeter <no@spam.no>
Newsgroups: pl.comp.lang.javascript
Subject: Re: dlaczego firstChild oraz childNodes[0] mam undefined?
Message-ID: <20170316120955.4c2fcf01@pe.regionet.pl>
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Xref: csiph.com pl.comp.lang.javascript:3295

Thu, 16 Mar 2017 00:49:40 -0700 (PDT)     =20
zpksoft <zpksoft@op.pl>   napisa=C5=82(a):

> > > Przecie=C5=BC wystarczy napisa=C4=87:
> > >=20
> > >   document.onclick =3D function(e){
> > >=20
> > >   e =3D e || window.event;
> > >   var t =3D e.target || e.srcElement;
> > >   n=3Dt.id || t.className;
> > >   if (!n) return;
> > > //i teraz obs=C5=82uga naszej aplikacji:
> > >=20
> > > if (n=3D=3D'id_diva1') {...}
> > > else if (n=3D=3D'id_elementu_span1') {...}
> > > else ... =20
> >=20
> > Po to si=C4=99 u=C5=BCywa framework=C3=B3w, by nie klepa=C4=87 r=C4=99c=
znie ca=C5=82ego tego =C5=9Bmietnika.
> >  =20

> Ja to widz=C4=99 inaczej. =C5=BBeby nie pisa=C4=87 tych kilku linijek kod=
u mam do=C5=82=C4=85czy=C4=87 ca=C5=82y
> framework? To jest dopiero =C5=9Bmietnik z tysi=C4=85cem linijek zb=C4=99=
dnego kodu.

Mia=C5=82by=C5=9B racj=C4=99, gdyby kod ko=C5=84czy=C5=82 si=C4=99 na tych =
kilku linijkach i potrzebowa=C5=82 jednej czy
dw=C3=B3ch funkcjonalno=C5=9Bci. Ale to ju=C5=BC raczej nie te czasy.
=20

--=20
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