X-Received: by 2002:a0c:ed4c:: with SMTP id v12mr15056893qvq.120.1586726298919; Sun, 12 Apr 2020 14:18:18 -0700 (PDT) X-Received: by 2002:a37:9e08:: with SMTP id h8mr6738357qke.369.1586726298735; Sun, 12 Apr 2020 14:18:18 -0700 (PDT) Path: csiph.com!xmission!news.snarked.org!border2.nntp.dca1.giganews.com!nntp.giganews.com!news-out.google.com!nntp.google.com!postnews.google.com!google-groups.googlegroups.com!not-for-mail Newsgroups: microsoft.public.sqlserver.programming Date: Sun, 12 Apr 2020 14:18:18 -0700 (PDT) In-Reply-To: Complaints-To: groups-abuse@google.com Injection-Info: google-groups.googlegroups.com; posting-host=173.162.45.17; posting-account=oUsksgoAAADjmotEgGTiI_3PeNLPQGJq NNTP-Posting-Host: 173.162.45.17 References: <32b39068-acc8-48ef-ac56-7f80bc2ee65b@googlegroups.com> <7a25939e-1e2d-4de3-9315-edef91428a1a@googlegroups.com> User-Agent: G2/1.0 MIME-Version: 1.0 Message-ID: <3e7cf417-607c-4659-aed2-d4c4668e592b@googlegroups.com> Subject: Re: How do I order the columns on a pivot table? From: John Hall Injection-Date: Sun, 12 Apr 2020 21:18:18 +0000 Content-Type: text/plain; charset="UTF-8" Lines: 48 Xref: csiph.com microsoft.public.sqlserver.programming:31362 On Sunday, April 12, 2020 at 4:31:07 PM UTC-4, Erland Sommarskog wrote: > John Hall (foundarecord@gmail.com) writes: > > On Sunday, April 12, 2020 at 7:59:26 AM UTC-4, Erland Sommarskog wrote: > >> SELECT PE.TestID, > >> MIN(CASE PU.PresentOrder WHEN 1 THEN PE.TextValue END) AS Param1, > >> MIN(CASE PU.PresentOrder WHEN 2 THEN PE.TextValue END) AS Param2, > >> MIN(CASE PU.PresentOrder WHEN 3 THEN PE.TextValue END) AS Param3, > >> MIN(CASE PU.PresentOrder WHEN 4 THEN PE.TextValue END) AS Param4, > >> MIN(CASE PU.PresentOrder WHEN 5 THEN PE.TextValue END) AS Param5 > >> FROM ParametersEntries PE > >> JOIN ParametersUser PU ON PE.TestID = PU.TestID > >> GROUP BY PE.TestID > > > > The SQL Management studio is saying this is a view not a pivot table and > > can't have an ORDER BY. I simplified this for my question. I need to > > order the results and JOIN it on TestID with yet another table. > > > > Could explain more closely what you are doing? The above is not a view, it > is a query, since, well, that seemed to be what you asked for. But > obviously, you could make a it view by adding CREATE VIEW on top. > > You cannot have ORDER BY in a view definition. SELECT DateTime, Param1, Param2, Param3, Param4, Param5, S1, S2, S3, S4, S5 FROM ( SELECT TOP 100 SubgroupID, DateTime, TestID FROM Subgroups WHERE CharID = 502107 AND DateTime < '04/22/2020' ORDER BY SubgroupID DESC ) s LEFT JOIN (SELECT PE.TestID, MIN(CASE PU.PresentOrder WHEN 1 THEN PE.TextValue END) AS Param1, MIN(CASE PU.PresentOrder WHEN 2 THEN PE.TextValue END) AS Param2, MIN(CASE PU.PresentOrder WHEN 3 THEN PE.TextValue END) AS Param3, MIN(CASE PU.PresentOrder WHEN 4 THEN PE.TextValue END) AS Param4, MIN(CASE PU.PresentOrder WHEN 5 THEN PE.TextValue END) AS Param5 FROM ParameterEntries PE JOIN ParametersUsed PU ON PE.ParameterID = PU.ParameterID WHERE TestID IN (SELECT TOP 100 TestID FROM Subgroups WHERE CharID = 502107 AND DateTime = '08/29/2017 10:29:25' ) GROUP BY PE.TestID) pv ON s.TestID = pv.TestID RIGHT JOIN (select SubgroupID, [1] as S1, [2] as S2, [3] as S3, [4] as S4, [5] as S5 from (select SubgroupID, Value, row_number() over(partition by SubgroupID order by SampleNumber) rnk from DataValues WHERE SubgroupID IN (SELECT TOP 100 SubgroupID FROM Subgroups WHERE CharID = 502107 AND DateTime < '04/22/2020' ORDER BY SubgroupID DESC) ) d pivot(max(Value) for rnk in ([1], [2], [3], [4], [5])) piv) pv2 ON s.SubgroupID = pv2.SubgroupID ORDER BY DateTime This time it didn't give an error but, returned NULL for all ParamX values and incorrect DataValues