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Re: Bash removes unrequested characters in bracket expressions (not a range).

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  Re: Bash removes unrequested characters in bracket expressions (not a range). Chet Ramey <chet.ramey@case.edu> - 2018-11-24 14:06 -0500

#14849 — Re: Bash removes unrequested characters in bracket expressions (not a range).

On 11/23/18 6:09 PM, Bize Ma wrote:

> Bash Version: 4.4
> Patch Level: 12
> Release Status: release
> 
> 
> 
> Description:
> 
> Bash is removing characters not explicitly listed in a bracket
> expression (character range).
> In this example, it is removing digits from other languages.
> 
> Also tested (and it fails) in bash 3.{0,1,3} 4.{1,2,3} and 5.0
> Not a problem in bash 2.{0,1}

I can't reproduce this:

$ cat ./x4

a='0123456789 ٠١٢٣٤٥٦٧٨٩ ۰۱۲۳۴۵۶۷۸۹ ߀߁߂߃߄߅߆߇߈߉ ०१२३४५६७८९'

recho "${a}"
recho "${a//[0123456789]}"
$ ../bash-5.0-beta2/bash ./x4
argv[1] = <0123456789 ٠١٢٣٤٥٦٧٨٩ ۰۱۲۳۴۵۶۷۸۹ ߀߁߂߃߄߅߆߇߈߉ ०१२३४५६७८९>
argv[1] = < ٠١٢٣٤٥٦٧٨٩ ۰۱۲۳۴۵۶۷۸۹ ߀߁߂߃߄߅߆߇߈߉ ०१२३४५६७८९>
$ ../bash-4.4-patched/bash ./x4
argv[1] = <0123456789 ٠١٢٣٤٥٦٧٨٩ ۰۱۲۳۴۵۶۷۸۹ ߀߁߂߃߄߅߆߇߈߉ ०१२३४५६७८९>
argv[1] = < ٠١٢٣٤٥٦٧٨٩ ۰۱۲۳۴۵۶۷۸۹ ߀߁߂߃߄߅߆߇߈߉ ०१२३४५६७८९>


-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
		 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU    chet@case.edu    http://tiswww.cwru.edu/~chet/

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