Re: \c-handling in $'-strings

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From	"Helmut Karlowski" <helmut.karlowski@ish.de>
Newsgroups	gnu.bash.bug
Subject	Re: \c-handling in $'-strings
Date	Wed, 02 Sep 2015 22:10:45 +0100
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Am 02.09.2015, 14:19 Uhr,SCHRIEB Chet Ramey <chet.ramey@case.edu>:

>> echo $'\c?' |od -a
>> echo $'\c[\c\\c]\c^\c_\c?' |od -a
>>
>> bash prints:
>>
>> 0000000  us  nl
>> 0000002
>> 0000000 esc  fs   c   ]  rs  us  us  nl
>>
>> I'd expect:
>>
>> 0000000 del  nl
>> 0000002
>> 0000000 esc  fs  gs  rs  us del  nl
>>
>> Also the ] in the output seems wrong, looks it gets the \\ wrong, though
>> ksh93 does this also.
>
> The Posix standardization of $'...' requires that the character after the

Where is that described? I could not find anything about $'...' in the  
posix-docs.

> `\c' honor backslash escaping.  Since the character becomes \c\\, the
> subsequent `c' and `]' are literals.

I assume this is only true for "to-be-escaped" characters, that is

$   `   "   \   <newline>

like for ".."-strings? Of course only \ is of interest here.

If that is true then the output of ksh93 for

echo $'\c\d' |od -a -> 0000000 eot  nl

is wrong? It removes the \ every time.

-Helmut

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Thread

\c-handling in $'-strings "Helmut Karlowski" <helmut.karlowski@ish.de> - 2015-08-29 00:28 +0100
  Re: \c-handling in $'-strings Chet Ramey <chet.ramey@case.edu> - 2015-08-31 10:17 -0400
    Re: \c-handling in $'-strings "Helmut Karlowski" <helmut.karlowski@ish.de> - 2015-09-01 23:46 +0100
      Re: \c-handling in $'-strings Chet Ramey <chet.ramey@case.edu> - 2015-09-02 09:19 -0400
        Re: \c-handling in $'-strings "Helmut Karlowski" <helmut.karlowski@ish.de> - 2015-09-02 22:10 +0100
          Re: \c-handling in $'-strings Eric Blake <eblake@redhat.com> - 2015-09-02 15:44 -0600
          Re: \c-handling in $'-strings Chet Ramey <chet.ramey@case.edu> - 2015-09-03 09:58 -0400

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