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extra \1 in declare -p

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Hi, about this bug:
http://lists.gnu.org/archive/html/bug-bash/2003-03/msg00093.html

The fix was to add this in lib/sh/shquote.c
      else if (c == CTLESC || c == CTLNUL)
        *r++ = CTLESC;

I think the fix it was applied twice, it should only check this in the
prompt string, right?


Now declare -p produces output that can't be eval'ed.

$ var=$'x\1y\177z'; declare -p var | sed -n l
declare -- var="x\001\001y\001\177z"$


Removing lines 151-152 (from the 4.4 alpha branch) seems to fix this.
The duplicate code keeps checking the prompt in lines 297-298.
(${var@P} is expanded by that part so it should be fine...)
I hope it won't cause other problems.


---
xoxo iza

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extra \1 in declare -p isabella parakiss <izaberina@gmail.com> - 2015-07-20 20:23 +0200

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