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Groups > gnu.bash.bug > #15065
| From | "" <kfm@plushkava.net> |
|---|---|
| Newsgroups | gnu.bash.bug |
| Subject | File descriptor of process substitution unexpectedly persisting |
| Date | 2019-06-21 19:58 +0100 |
| Message-ID | <mailman.609.1561150004.10840.bug-bash@gnu.org> (permalink) |
| References | <20190621195822.be84baf077ebe5dfda8b72ae@plushkava.net> |
Hi,
As tested interactively with bash 5.0.7(1) and GNU/Linux, the following command prints a constant number of active file descriptors, as expected:
$ while :; do { read; } < <(:); sleep 0.5; printf %s\\n /proc/self/fd/* | wc -l; done
6
6
6
6
6
... etc
However, merely by assigning a variable prior to the loop, though within the same line, the number will continuously grow:
$ var=0; while :; do { read; } < <(:); sleep 0.5; printf %s\\n /proc/self/fd/* | wc -l; done
6
7
8
9
10
... etc
If then adjusted so that the read command is not part of a compound command, normality is restored:
$ var=0; while :; do read < <(:); sleep 0.5; printf %s\\n /proc/self/fd/* | wc -l; done
5
5
5
5
5
... etc
I noticed this behaviour upon running out of file descriptors after executing structurally similar code that deliberately utilises a compound command to read twice, thus discarding the first line of input.
--
Kerin Millar <kfm@plushkava.net>
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File descriptor of process substitution unexpectedly persisting "" <kfm@plushkava.net> - 2019-06-21 19:58 +0100
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