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| From | Chet Ramey <chet.ramey@case.edu> |
| Newsgroups | gnu.bash.bug |
| Subject | Re: \? is missing in "3.1.2.4 ANSI-C Quoting" in Bash Reference Manual |
| Date | Thu, 3 Sep 2015 15:07:05 -0400 |
| Lines | 30 |
| Approved | bug-bash@gnu.org |
| Message-ID | <mailman.471.1441307237.19560.bug-bash@gnu.org> (permalink) |
| References | <5A6BF229-3DFC-4D2E-977A-086612B9D740@qq.com> <55E716A3.1070701@case.edu> <5C938A0B-E5C0-4C8A-AA48-2C65E77DCAAA@qq.com> |
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| To | ziyunfei <446240525@qq.com> |
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On 9/2/15 11:46 PM, ziyunfei wrote: > Sorry, I didn't understand your reply. What I'm saying is this: \? is shown > in printf section: > > "Causes printf to expand backslash escape sequences in the corresponding > argument, except that ‘\c’ terminates output, backslashes in ‘\'’, ‘\"’, > and ‘\?’ are not removed, and octal escapes beginning with ‘\0’ may contain > up to four digits.” > > but it isn't documented > in https://www.gnu.org/software/bash/manual/html_node/ANSI_002dC-Quoting.html correspondingly > after \’ and \”. I guess I see what you're saying: that bash removes the backslash quoting the `?' when processing $'...' but leaves backslashes escaping other characters not listed in the description of $'...' unchanged. I can add that to the documentation. If that's not what you mean, I guess I don't understand. `printf %b' expands one set of backslash escapes, and $'...' expands a slightly different set, since they're trying to serve slightly different purposes and have different origins. They're separate constructs and are documented separately. Chet -- ``The lyf so short, the craft so long to lerne.'' - Chaucer ``Ars longa, vita brevis'' - Hippocrates Chet Ramey, ITS, CWRU chet@case.edu http://cnswww.cns.cwru.edu/~chet/
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Re: \? is missing in "3.1.2.4 ANSI-C Quoting" in Bash Reference Manual Chet Ramey <chet.ramey@case.edu> - 2015-09-03 15:07 -0400
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