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From: Greg Wooledge <wooledg@eeg.ccf.org>
Newsgroups: gnu.bash.bug
Subject: Re: declare(1) not executing inside source'd script
Date: Fri, 27 Jul 2018 10:17:01 -0400
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On Fri, Jul 27, 2018 at 12:26:06AM -0400, frank@eec.com wrote:
> Repeat-By:
> 	$ cat <<__EOF__ >/tmp/bashbug.bash
> 	> function myfunc {
> 	>     echo "Running..."
> 	> }
> 	> declare -fx myfunc
> 	> declare -p -F | grep "myfunc"
> 	> __EOF__
> 	$ source /tmp/bashbug.bash
> 
> 	The function is now defined, but is not exported.
> 	And the output of the last command never appears,
> 	but if the same command is executed now -- at
> 	the interactive shell prompt -- it does show that
> 	'myfunc' is defined.

I cannot reproduce this, either in Debian's bash 4.4, or in bash 5.0-alpha.

wooledg:~$ exec bash-5.0-alpha
wooledg:~$ cat foo
function myfunc {
  echo "Running"
}
declare -fx myfunc
declare -p -F | grep myfunc
wooledg:~$ source ./foo
declare -fx myfunc
wooledg:~$ bash -c myfunc
Running

On my system, I see the output from "declare -p -F" upon sourcing the
file, and the function is definitely exported.  I get the same results
using Debian's bash 4.4(.12) as well.