Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]

Groups > gnu.bash.bug > #11624

Re: trap DEBUG and $_

Show all headers | View raw

On Mon, Oct 12, 2015 at 07:24:00AM +0200, isabella parakiss wrote:
> On 10/11/15, Dan Stromberg <dstromberglists@gmail.com> wrote:
> > Is there a way of outputting a datestamp to shell stderr at the _beginning_
> > of the execution of a command, that won't wipe out $_?
> >
> > I use $_ quite a bit for the last argument to the previous command,
> > interactively.  And I'd like to datestamp all my commands. Datestamping
> > after with $PS1 is easy, but datestamping before is a little harder.
> >
> > I've tried using:
> >
> >    function preexec { if tty -s; then echo "$(tput smso)cmd started $(date
> > +%Y\ %a\ %b\ %d\ %r)$(tput rmso)"; fi; }
> >    trap preexec DEBUG
> >
> > ...but as you might suspect, I'm finding that $_ is always "preexec" with
> > this enabled.
> >
> > Any suggestions?
> >
> > Thanks!
> >
> trap '__=$_; preexec; : "$__"' DEBUG

And since the preexec function ignores its arguments, it can be
shortened to:

    trap 'preexec "$_"' DEBUG

-- 
Geir Hauge

Back to gnu.bash.bug | Previous | Next | Find similar

Thread

Re: trap DEBUG and $_ Geir Hauge <geir.hauge@gmail.com> - 2015-10-12 09:13 +0200

csiph-web