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Groups > gnu.bash.bug > #11623
| From | isabella parakiss <izaberina@gmail.com> |
|---|---|
| Newsgroups | gnu.bash.bug |
| Subject | Re: trap DEBUG and $_ |
| Date | 2015-10-12 07:24 +0200 |
| Message-ID | <mailman.120.1444627443.7904.bug-bash@gnu.org> (permalink) |
| References | <CAEf4Emd6m+JZd3ECqYknU-P3Nz25zyNw+4-BG-0TKy+Fa1hFOg@mail.gmail.com> |
On 10/11/15, Dan Stromberg <dstromberglists@gmail.com> wrote:
> Is there a way of outputting a datestamp to shell stderr at the _beginning_
> of the execution of a command, that won't wipe out $_?
>
> I use $_ quite a bit for the last argument to the previous command,
> interactively. And I'd like to datestamp all my commands. Datestamping
> after with $PS1 is easy, but datestamping before is a little harder.
>
> I've tried using:
>
> function preexec { if tty -s; then echo "$(tput smso)cmd started $(date
> +%Y\ %a\ %b\ %d\ %r)$(tput rmso)"; fi; }
> trap preexec DEBUG
>
> ...but as you might suspect, I'm finding that $_ is always "preexec" with
> this enabled.
>
> Any suggestions?
>
> Thanks!
>
trap '__=$_; preexec; : "$__"' DEBUG
---
xoxo iza
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Re: trap DEBUG and $_ isabella parakiss <izaberina@gmail.com> - 2015-10-12 07:24 +0200
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