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| From | Simon <shadragon@excite.com> |
|---|---|
| Newsgroups | geometry.college |
| Subject | Three Sided Pyramid Volume Question. |
| Date | 2017-11-08 19:44 +0000 |
| Organization | The Math Forum |
| Message-ID | <273378439.231262.1510170224492.JavaMail.root@sodium.mathforum.org> (permalink) |
For the record I'm 56, so this isn't homework. :) I've enclosed a diagram of the problem I'm working for reference. Start with a cube. All edges are the same value. For reference, the corners of the cube are designated by numbers, the middle point of each edge is identified by a letter. Clear as mud? I need to take away the corners and determine the volume without them. One corner is determined by lines from A -> D D -> F F -> A Assuming each edge is 3.720, the middle point (from 1 -> D or D -> 4) is 1.860. Finding the distance from A -> D is found by simple trig to be 2.63044 The volume of a three sided pyramid can be found with the formula V = 1/3AH A = area of the triangle base. H = height of the pyramid. I know A = 2.99611, but how do I find H or the height in that scenario? Once I know that I can multiply corner volume by 8 to get the volume of all eight corners and subtract it from the whole. Thanks. Attachment available from http://mathforum.org/kb/forum.jspa?forumID=125
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Three Sided Pyramid Volume Question. Simon <shadragon@excite.com> - 2017-11-08 19:44 +0000
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