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From: Reimar Bauer <rb.proj@gmail.com>
Newsgroups: de.comp.lang.python
Subject: Re: [Python-de] Python3 - pathlib - python-gnupg Problem
Date: Tue, 6 Feb 2018 13:08:13 +0100
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Xref: csiph.com de.comp.lang.python:5116

Hi Zusammen,

evtl. magst dich auch mal damit befassen, das l=C3=B6st einige OS Probleme =
f=C3=BCr
mich, abgesehen davon das man auch entfernte Dateisysteme einheitlich
erreicht.

http://pyfilesystem2.readthedocs.io/en/latest/

Gr=C3=BC=C3=9Fe
Reimar




2018-02-06 13:00 GMT+01:00 Maurice Kemmann via python-de <
python-de@python.org>:

> Hi Zusammen,
>
> Am Dienstag, 6. Februar 2018 09:23:07 UTC+1 schrieb Maurice Kemmann:
> > Hallo,
> >
> > ich nutze pathlib um OS unabh=C3=A4ngige Scripte zu schreiben. Im Momen=
t
> spiele ich ein wenig mit python-gnupg herrum und laufe in folgendes Probl=
em:
> >
> > <code>
> > import gnupg
> > from pathlib import Path
> > from pprint import pprint
> >
> > gpg =3D gnupg.GPG(gnupghome=3DPath("/home/mucki/.gnupg/"))
> > <\code>
> >
> > Das f=C3=BChrt zu folgenden Fehler unter Linux:
> >
>
> Problem gel=C3=B6st.
>
> gpg =3D gnupg.GPG(gnupghome=3Dstr(Path("/home/mucki/.gnupg/")))
>
> Path liefert in diesem Fall wohl keinen String zu=C3=BCck, da habe ich wo=
hl die
> Doku nicht richtig gelesen. Danke an Uwe!
>
> Maurice
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