Path: csiph.com!fu-berlin.de!uni-berlin.de!not-for-mail From: eilfh Newsgroups: de.comp.lang.python Subject: [Python-de] Anfaengerfrage: Dataframe - Zeilenmittel - Spaltenmittel Date: Mon, 17 Jun 2019 22:37:10 +0200 Organization: eilfh Lines: 25 Message-ID: References: <1825444.o0KX4FVeTt@host> Mime-Version: 1.0 Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable X-Trace: news.uni-berlin.de nbFMXLziE8Ld5Pgpxcx4Ygzo9ht5eFzSmBLyzZdHzgkQ== Return-Path: X-Original-To: python-de@python.org Delivered-To: python-de@mail.python.org DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/simple; d=posteo.de; s=2017; t=1560803837; bh=Jtp/RDwoffJI4f3o9Ia6OM6uEfGMYzIZWrA2WHDKkww=; h=From:To:Subject:Date:From; b=WJeHEd9pu4tjEx0/mY36r1fneanvbCLAmbrMpRdKLnNxcXXFeHOcAnhAYLW1JF+Um COmgH5qPzQdYTbJ0Sy9kzmkevWdfNgIgdpFnZ8wBSoybCKeWaRsVMLsMWQKYrKAgAX W93IKrKi1CoEn4/xUZAkHuE9EgndW81vC5Te08uEpm0/9S5S/EcFT38rAcBAojh24g AwWngFcpijomq9cQBczUiCt/0WWk63XzkbClXAxspfXaMKOZjREeoEolgP8XdE/3W3 kAt2BcXNtbTaI37mKGt5S+lobzCgAisFYp+ByROOEarf1U1MIriYFXGsw1Q3n7w2wJ 40jWsPGPq45DQ== X-BeenThere: python-de@python.org X-Mailman-Version: 2.1.29 Precedence: list List-Id: Die Deutsche Python Mailingliste List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , X-Mailman-Original-Message-ID: <1825444.o0KX4FVeTt@host> Xref: csiph.com de.comp.lang.python:5489 hallo,=20 dumme Frage Anf=E4ngerfrage find einfach keine passende L=F6sung ungef=E4hr so for i in spalte_nr:=20 for j in zeilen_nr: DataFrame_1 =3D DataFrame -=20 Zeilen_mittel(DataFrame[j]) -=20 Spalte_mittel(DataFrame[i]) Die Komponenten der Berechnung hab ich zwar, aber in der doppelten for- Schleife gelingt mir das einfach nicht. =20 Vielen Dank im Voraus =46rank