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Newsgroups: de.comp.lang.python
Date: Tue, 6 Feb 2018 00:23:06 -0800 (PST)
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Subject: Python3 - pathlib - python-gnupg Problem
From: Maurice Kemmann <muckisg@googlemail.com>
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Xref: csiph.com de.comp.lang.python:5114

Hallo,

ich nutze pathlib um OS unabh=C3=A4ngige Scripte zu schreiben. Im Moment sp=
iele ich ein wenig mit python-gnupg herrum und laufe in folgendes Problem:

<code>
import gnupg
from pathlib import Path=20
from pprint import pprint

gpg =3D gnupg.GPG(gnupghome=3DPath("/home/mucki/.gnupg/"))
<\code>

Das f=C3=BChrt zu folgenden Fehler unter Linux:

>> python3 gpg-test.py=20

Traceback (most recent call last):
  File "gpg-test.py", line 5, in <module>
    gpg =3D gnupg.GPG(gnupghome=3DPath("/home/mucki/.gnupg/"))
  File "/usr/local/lib/python3.6/site-packages/gnupg.py", line 755, in __in=
it__
    p =3D self._open_subprocess(["--version"])
  File "/usr/local/lib/python3.6/site-packages/gnupg.py", line 832, in _ope=
n_subprocess
    logger.debug("%s: %s", result.pid, debug_print(cmd))
  File "/usr/lib64/python3.6/subprocess.py", line 461, in list2cmdline
    needquote =3D (" " in arg) or ("\t" in arg) or not arg
TypeError: argument of type 'PosixPath' is not iterable

Unter Windows 10 gibt es eine passende Fehlermeldung mit "type WindowsPath =
not iterable".

Es scheint ja mit dem subprocess module zusammenzuh=C3=A4ngen, aber hier h=
=C3=B6rt mein Wissen leider auf. Kann mir jemand helfen? Liegt der Fehler b=
ei mir? Wenn ja, warum?

Danke,

Maurice