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From: Peter 'Shaggy' Haywood <phaywood@alphalink.com.au>
Newsgroups: comp.sys.apple2.programmer
Subject: Re: malloc with cc65
Date: Wed, 27 Dec 2023 10:00:43 +1100
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Groovy hepcat Bill Chatfield was jivin' in comp.sys.apple2.programmer on
Thu, 21 Dec 2023 02:52 am. It's a cool scene! Dig it.

> On Mon, 18 Dec 2023 19:51:58 -0000 (UTC)
> Oliver Schmidt <ol.sc@web.de> wrote:
> 
>> No, the syntax above isn't for assigning a value to a pointer. It's
>> for assigning a value to the address the pointer points to.
> 
> OMG, it's been too long since I've written C code. Of, course you're
> right and I knew that. The overloading of the * operator in one place
> to define a pointer and in another place, the exact opposite, to
> access the data pointed to by a pointer, has always perplexed me.

  There's no overloading going on here (notwithstanding its use the
multiplication operator). It's really quite simple. The * operator
means "the object pointed at". When used in a declaration it still
means "the object pointed at". A pointer to foo (where foo is a type)
declaration essentially means, "Declare an object which is a pointer
such that the object pointed at by it is a foo."

-- 


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