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From: Bill Chatfield <bill_chatfield@yahoo.com>
Newsgroups: comp.sys.apple2.programmer
Subject: Re: malloc with cc65
Date: Sun, 31 Dec 2023 11:58:19 -0500
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On Wed, 27 Dec 2023 10:00:43 +1100
Peter 'Shaggy' Haywood <phaywood@alphalink.com.au> wrote:

>   There's no overloading going on here (notwithstanding its use the
> multiplication operator). It's really quite simple. The * operator
> means "the object pointed at". When used in a declaration it still
> means "the object pointed at". A pointer to foo (where foo is a type)
> declaration essentially means, "Declare an object which is a pointer
> such that the object pointed at by it is a foo."

I see what you're saying, after much mind bending. Maybe that is the
correct way to think about it.

The way I was thinking about it, in the declaration, the * produces a
pointer. In an expression the * produces data from a pointer.