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Re: Solving Equations with 3 variables and many parameters

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From	roby <roby.nowak@gmail.com>
Newsgroups	comp.soft-sys.math.mathematica
Subject	Re: Solving Equations with 3 variables and many parameters
Date	Mon, 3 Mar 2014 02:38:24 +0000 (UTC)
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Hi,

you have to use the equality operator ==
not the assginment operator =

Solve[{P1==(a[1]+C*b[11]+b[12]*P2+b[13]*P3)/(2*b[11]), P2==(a[2]+C*b[22]+b[21]*P1+b[23]*P3)/(2*b[22]), P3==(a[3]+C*b[33]+b[31]*P1+b[32]*P2/(2*b[33])}, {P1, P2, P3}]

Cheers Robert



Am Sonntag, 2. M=E4rz 2014 07:46:49 UTC+1 schrieb drascher:
> Hello,
>
>
>
> I am able to get Mathematica to solve:
>
>
>
> Solve[{P1=(a[1]+C*b[11]+b[12]*P2)/(2*b[11]), P2=(a[2]+C*b[22]+b[21]*P1)/(2*b[22])}, {P1, P2}]
>
>
>
> but it won't solve the following (which is one more variable P3 and its equation):
>
>
>
> Solve[{P1=(a[1]+C*b[11]+b[12]*P2+b[13]*P3)/(2*b[11]), P2=(a[2]+C*b[22]+b[21]*P1+b[23]*P3)/(2*b[22]), P3=(a[3]+C*b[33]+b[31]*P1+b[32]*P2)/(2*b[33])}, {P1, P2, P3}]
>
>
>
> It says that it doesn't understand how to interpret the word "Solve" even though it does it for the first eqn.
>
>
>
> Any help is appreciated.

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Thread

Solving Equations with 3 variables and many parameters drascher <rascher@usfca.edu> - 2014-03-02 06:46 +0000
  Re: Solving Equations with 3 variables and many parameters roby <roby.nowak@gmail.com> - 2014-03-03 02:29 +0000
  Re: Solving Equations with 3 variables and many parameters roby <roby.nowak@gmail.com> - 2014-03-03 02:38 +0000

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