Path: csiph.com!v102.xanadu-bbs.net!xanadu-bbs.net!feeder.erje.net!us.feeder.erje.net!newsfeed.fsmpi.rwth-aachen.de!news-1.dfn.de!news.dfn.de!fu-berlin.de!uni-berlin.de!individual.net!not-for-mail From: Axel Vogt <&noreply@axelvogt.de> Newsgroups: comp.soft-sys.math.maple Subject: Re: A zeta function limit Date: Tue, 09 Jul 2013 21:00:52 +0200 Lines: 24 Message-ID: References: <853ced10-e2b6-4aa9-9518-4426959beb6b@googlegroups.com> Reply-To: &noreply@axelvogt.de Mime-Version: 1.0 Content-Type: text/plain; charset=ISO-8859-1 Content-Transfer-Encoding: 7bit X-Trace: individual.net 6xt4ICx51TNFszyfIozAOwfLVIbQTW2lS2DhIT6JgWwB+Fvgg= Cancel-Lock: sha1:jfzJEisWZC7iwnakOcPsBABPXFo= User-Agent: Mozilla/5.0 (Windows NT 6.1; WOW64; rv:17.0) Gecko/20130620 Thunderbird/17.0.7 In-Reply-To: <853ced10-e2b6-4aa9-9518-4426959beb6b@googlegroups.com> Xref: csiph.com comp.soft-sys.math.maple:783 On 09.07.2013 19:28, peter.luschny@gmail.com wrote: > With Maple V R5 I get > > f := z -> -(-Zeta(1-z)+z*Zeta(1,1-z))/(z*Zeta(1-z)); > limit(f(z), z=0); > > MAPLE> -gamma > > But looking at the plot kindly provided by Wolfram Alpha > I feel unsure if this is correct. > > Limit[(-Zeta[1 - z] + z D[Zeta[1 - z], z])/(-(z Zeta[1 - z])), z->0] > > Peter > Using M17 also gives me that (the alternative MultiSeries does it as well), and f(1e-12) is close (even with 100 decimal places. Plotting with y-range fits with that, plot(f(z), z=0 .. 1, -1 .. 0); However the Maple equivalent for z D[Zeta[1 - z], z] is z*diff(Zeta(1-z),z) = - z*Zeta(1,1-z) while in your f you have a '+' sign, you have D(Zeta)(1-z) there.