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From: Joe Riel <joer@san.rr.com>
Newsgroups: comp.soft-sys.math.maple
Subject: Re: A hypergeometric formula
Date: Wed, 10 Sep 2014 09:05:22 -0700
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peter.luschny@gmail.com writes:

> 2*GAMMA(3/2)*hypergeom([1/2,0],[3/2,0,-1/2],-1) /sqrt(Pi) = ?
>
> Peter

(**) y := 2*GAMMA(3/2)*hypergeom([1/2,0],[3/2,0,-1/2],-1) /sqrt(Pi);
                                y := hypergeom([1/2], [-1/2, 3/2], -1)

(**) simplify(y);
                                         sin(2) - cos(2)


-- 
Joe Riel