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Re: C Programming under Windows

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On Mon, 1 Oct 2012 23:04:51 -0700 (PDT), adityaismagic@gmail.com
wrote:

>HELP ME, PLEASE...
>i am developing software for some frnds of civil engg. dept. topic - Hydraulic Design for Sewage waste-water treatment, Grit Chamber Designing. I wrote program but it gives floating point overflow error.
>In code c_area variable goes to float overflow. how to convert data type of c_area, (%2.4f) i.e. xx.xxxx.
>I tried to search on google for help but till no solution found.
>If you will find answer please email me, because i don't know how this google group works, my id adityaismagic@gmail.com , Thank You.
>my code is_____________

I very rarely use email to discuss problems raised in forums. Everyone
should be able to see and benefit from all the questions and answers,
unless they become unusually obscure.

>
>	printf("\n\n Enter Horizontal velocity / Flow through velocity (in m/sec) : ");//assume 0.23 m/sec//
>	scanf("%2.4f",h_velocity);
>	c_area = peakflow/h_velocity;//overflow happens here, how to convert this value into %2.4f //

Overflow is very likely to happen when the denominator is small or
zero, so you should _always_ check denominator before division. And
you should always check that user input is at least reasonable.

Nothing in C is stored as %2.4f, except for numbers stored as
character strings. You can use printf to convert a float into a
character string, or just print it as you do. The printf function
takes formatting arguments similar to scanf.

>	printf("\n Cross Sectional area : %f sq.m",c_area);

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Robert E. Zaret
PenFact, Inc.
20 Park Plaza, Suite 400
Boston, MA 02116
www.penfact.com
Useful reading (be sure to read its disclaimer first):
   http://catb.org/~esr/faqs/smart-questions.html

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Re: C Programming under Windows adityaismagic@gmail.com - 2012-10-01 23:04 -0700
  Re: C Programming under Windows r_z_aret@pen_fact.com - 2012-10-02 11:43 -0400
    Re: C Programming under Windows r_z_aret@pen_fact.com - 2012-10-02 12:47 -0400

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