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basic bytecode to machine code compiler (part 3)

Started byRouslan Korneychuk <rouslank@msn.com>
First post2011-06-20 19:47 -0400
Last post2011-06-21 16:06 -0400
Articles 3 — 2 participants

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  basic bytecode to machine code compiler (part 3) Rouslan Korneychuk <rouslank@msn.com> - 2011-06-20 19:47 -0400
    Re: basic bytecode to machine code compiler (part 3) Ulrich Eckhardt <ulrich.eckhardt@dominolaser.com> - 2011-06-21 12:55 +0200
      Re: basic bytecode to machine code compiler (part 3) Rouslan Korneychuk <rouslank@msn.com> - 2011-06-21 16:06 -0400

#8038 — basic bytecode to machine code compiler (part 3)

FromRouslan Korneychuk <rouslank@msn.com>
Date2011-06-20 19:47 -0400
Subjectbasic bytecode to machine code compiler (part 3)
Message-ID<1_QLp.10563$xh5.2244@newsfe02.iad>
My compiler now supports the x86-64 instruction set, in addition to x86. 
It also generates faster x86 machine code.

Although it's designed to support 64-bit Windows, I have only tested it 
on Linux so far, and it doesn't support running with Windows' DEP yet.

It's available at https://github.com/Rouslan/nativecompile

Here are the new benchmark results. The 64-bit code has a better margin 
of improvement even though the Python interpreter is already faster in 
64-bit mode.


The first test performs a quicksort on a list of 100 numbers, 5000 
times. The second calculates all the prime numbers up to 10000000. Each 
test is run three times in a row, first with the interpreter, then with 
the compiled code.

#### SCRIPT ONE ####

import time
import random
import nativecompile

bcode = compile('''
def quicksort(array):
     if len(array) <= 1:
         return array
     pindex = len(array)//2
     pivot = array[pindex]
     less = []
     greater = []
     for i,x in enumerate(array):
         if i != pindex:
             (less if x <= pivot else greater).append(x)
     return quicksort(less) + [pivot] + quicksort(greater)

in_ = list(range(100))
random.seed(346097)
random.shuffle(in_)

t = time.clock()
for x in range(5000):
     out = quicksort(in_)
t = time.clock()-t

assert out == sorted(in_)

print('execution time: {}'.format(round(t,10)))
''','<string>','exec')

mcode = nativecompile.compile(bcode)

print('byte code')
for x in range(3): eval(bcode)
print()

print('machine code')
for x in range(3): mcode()
print()

#### X86 OUTPUT ####

byte code
execution time: 1.76
execution time: 1.75
execution time: 1.77

machine code
execution time: 1.43
execution time: 1.43
execution time: 1.43

#### X86-64 OUTPUT ####

byte code
execution time: 1.49
execution time: 1.48
execution time: 1.48

machine code
execution time: 1.17
execution time: 1.17
execution time: 1.17



#### SCRIPT TWO ####

import time
import math
import nativecompile

bcode = compile('''
def primes_list(upto):
     nums = [True] * (upto//2-1)

     for i in range(3,math.floor(math.sqrt(upto))+1,2):
         if nums[i//2-1]:
             for j in range(i*3,upto,i*2):
                 nums[j//2-1] = False

     primes = []
     for i,n in enumerate(nums):
         if n: primes.append((i+1)*2+1)

     return primes

t = time.clock()
primes = primes_list(10000000)
t = time.clock()-t

print(primes[-1])
print('execution time: {}'.format(round(t,10)))
''','<string>','exec')

mcode = nativecompile.compile(bcode)

print('byte code')
for x in range(3): eval(bcode)
print()

print('machine code')
for x in range(3): mcode()
print()

#### X86 OUTPUT ####

byte code
9999991
execution time: 3.57
9999991
execution time: 3.34
9999991
execution time: 3.37

machine code
9999991
execution time: 2.73
9999991
execution time: 2.67
9999991
execution time: 2.73

#### X86-64 OUTPUT ####

byte code
9999991
execution time: 3.05
9999991
execution time: 3.24
9999991
execution time: 3.17

machine code
9999991
execution time: 2.15
9999991
execution time: 2.17
9999991
execution time: 2.17

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#8083

FromUlrich Eckhardt <ulrich.eckhardt@dominolaser.com>
Date2011-06-21 12:55 +0200
Message-ID<ol96d8-hhd.ln1@satorlaser.homedns.org>
In reply to#8038
Rouslan Korneychuk wrote:
> if i != pindex:
>     (less if x <= pivot else greater).append(x)

Just curious, is there a reason why you wrote this last line that way 
instead of using a "normal" if/else clause?


Cheers!

Uli


-- 
Domino Laser GmbH
Geschäftsführer: Thorsten Föcking, Amtsgericht Hamburg HR B62 932

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#8121

FromRouslan Korneychuk <rouslank@msn.com>
Date2011-06-21 16:06 -0400
Message-ID<cR6Mp.10110$PA5.6044@newsfe01.iad>
In reply to#8083
On 06/21/2011 06:55 AM, Ulrich Eckhardt wrote:
> Rouslan Korneychuk wrote:
>> if i != pindex:
>>      (less if x<= pivot else greater).append(x)
>
> Just curious, is there a reason why you wrote this last line that way
> instead of using a "normal" if/else clause?
>
>
> Cheers!
>
> Uli
>
>

No special reason. I just like concise code.

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