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opening a file

Started byTim Hanson <tjhanson@yahoo.com>
First post2011-06-19 23:00 -0700
Last post2011-06-20 11:01 +0100
Articles 2 — 2 participants

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  opening a file Tim Hanson <tjhanson@yahoo.com> - 2011-06-19 23:00 -0700
    Re: opening a file Nobody <nobody@nowhere.com> - 2011-06-20 11:01 +0100

#8000 — opening a file

FromTim Hanson <tjhanson@yahoo.com>
Date2011-06-19 23:00 -0700
Subjectopening a file
Message-ID<mailman.170.1308550055.1164.python-list@python.org>
Using linux and Python 2.6, learning how to work with files from a Windows 
oriented textbook:

This works:
infile=open('/foo/bar/prog/py_modules/this_is_a_test','r')

This doesn't:
infile=open('~/prog/py_modules/this_is_a_test','r')

Can't I work with files using Unix expressions?

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#8008

FromNobody <nobody@nowhere.com>
Date2011-06-20 11:01 +0100
Message-ID<pan.2011.06.20.10.00.23.375000@nowhere.com>
In reply to#8000
On Sun, 19 Jun 2011 23:00:38 -0700, Tim Hanson wrote:

> This works:
> infile=open('/foo/bar/prog/py_modules/this_is_a_test','r')
> 
> This doesn't:
> infile=open('~/prog/py_modules/this_is_a_test','r')
> 
> Can't I work with files using Unix expressions?

The argument is treated literally, just like C's fopen() etc. If you want
substitions, you have to perform them explicitly, e.g.:

infile=open(os.path.expanduser('~/prog/py_modules/this_is_a_test'),'r')

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