Path: csiph.com!usenet.pasdenom.info!news.albasani.net!newsfeed.freenet.ag!news2.euro.net!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail
Date: Mon, 26 Mar 2012 11:24:03 +0200
From: Michael Poeltl <michael.poeltl@univie.ac.at>
To: Nikhil Verma <varma.nikhil22@gmail.com>
Subject: Re: random number
References: <CABgq=FyhR+Ldujj3YKRBpVXRVoeoayuXZviUUcNx-gXnFiHLSw@mail.gmail.com> <20120326064000.GB19865@terra.cms.at> <CABgq=FwMuHR1nJiaCDiTJAE4Y_3y6WRhZ2DOMaYYC=ex_gT93g@mail.gmail.com>
MIME-Version: 1.0
Content-Type: text/plain; charset=us-ascii
Content-Disposition: inline
In-Reply-To: <CABgq=FwMuHR1nJiaCDiTJAE4Y_3y6WRhZ2DOMaYYC=ex_gT93g@mail.gmail.com>
User-Agent: Mutt/1.5.21 (2010-09-15)
Cc: python-list@python.org
Precedence: list
Newsgroups: comp.lang.python
Message-ID: <mailman.986.1332753846.3037.python-list@python.org>
Lines: 86
NNTP-Posting-Host: 2001:888:2000:d::a6
Xref: csiph.com comp.lang.python:22165

* Nikhil Verma <varma.nikhil22@gmail.com> [2012-03-26 08:49]:
> Hi
> 
> I want something to achieve like this :-
> 
> def random_number(id): # I am passing it from request
>     # do something
>     return random_number
> 
> Output
> 
> random_number(5)
> AXR670
> 
> One input that is a number in return you are getting 6 digit alphanumeric
> string.
> 
> I tried this
> s = '%06d' % random.randint(0, 999999)
> 
> it gives : '192862' (a string )
> 
> Thanks in advance.
ah - so I misunderstood - I thought you want a permutation of a given
6-digit number

It's still not quite clear to me what role 'id' is playing ... so let's
check this one;
and Steven, who is maybe more experienced than I am will help us ufrther

>>> import random, string
>>> def random_number(id):
...     characters = list(string.ascii_lowercase +
...                       string.ascii_uppercase +
...                       string.digits)
...     coll_rand = []
...     for i in range(6):
...         random.shuffle(characters)
...         coll_rand.append(characters[0])
...     return ''.join(coll_rand)
... 
>>> id = 5
>>> print (random_number(id))
puMHCr
>>>

regards
Michael


> 
> On Mon, Mar 26, 2012 at 12:10 PM, Michael Poeltl <
> michael.poeltl@univie.ac.at> wrote:
> 
> > * Nikhil Verma <varma.nikhil22@gmail.com> [2012-03-26 08:09]:
> > > Hi All
> > >
> > > How can we generate a 6 digit random number from a given number ?
> > what about this?
> >
> > >>> given_number=123456
> > >>> def rand_given_number(x):
> > ...     s = list(str(x))
> > ...     random.shuffle(s)
> > ...     return int(''.join(s))
> > ...
> > >>> print (rand_given_number(given_number))
> > 653421
> >
> 
> 
> 
> -- 
> Regards
> Nikhil Verma
> +91-958-273-3156


-- 
Michael Poeltl
Computational Materials Physics      voice: +43-1-4277-51409
Univ. Wien, Sensengasse 8/12         fax:   +43-1-4277-9514 (or 9513) 
A-1090 Wien, AUSTRIA   cmp.mpi.univie.ac.at 
-------------------------------------------------------------------------------
ubuntu-11.10 | vim-7.3 | python-3.2.2 | mutt-1.5.21 | elinks-0.12
-------------------------------------------------------------------------------