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Date: Fri, 29 Apr 2011 15:19:23 +1100
Subject: Re: use of index (beginner's question)
From: Daniel Kluev <dan.kluev@gmail.com>
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Xref: x330-a1.tempe.blueboxinc.net comp.lang.python:4294

On Thu, Apr 28, 2011 at 11:42 AM, Rusty Scalf <iai-gis@sonic.net> wrote:
> list1 =3D ['pig', 'horse', 'moose']
> list2 =3D =A0['62327', '49123', '79115']
> n =3D 2
> s2 =3D "list" + `n`
> a =3D s2[list1.index('horse')]
> print a
>
> =A0-does not work

While advices above are indeed right way to go in your case, there is
a way to get variable by its name.

>>> list2 =3D ['62327', '49123', '79115']
>>> n =3D 2
>>> s2 =3D "list{0}".format(n)
>>> print s2
list2
>>> print locals()[s2]
['62327', '49123', '79115']
>>> print locals()[s2][0]
62327

But generally if you need to do that, you would be better with
re-design of your data/architecture.

--=20
With best regards,
Daniel Kluev