Path: csiph.com!fu-berlin.de!uni-berlin.de!not-for-mail From: Chris Angelico Newsgroups: comp.lang.python Subject: Re: Returning a result from 3 items in a list Date: Tue, 24 Nov 2015 21:14:19 +1100 Lines: 28 Message-ID: References: <133829df-f57f-442f-9dbf-b22b22f656ae@googlegroups.com> Mime-Version: 1.0 Content-Type: text/plain; charset=UTF-8 X-Trace: news.uni-berlin.de vZiFxz+4HQyZquLJr7IHswiaxA9AVFQL/5aMkhxlU0MA== Return-Path: X-Original-To: python-list@python.org Delivered-To: python-list@mail.python.org X-Spam-Status: OK 0.016 X-Spam-Evidence: '*H*': 0.97; '*S*': 0.00; 'received:209.85.223': 0.03; 'cc:addr:python-list': 0.09; '24,': 0.16; 'from:addr:rosuav': 0.16; 'from:name:chris angelico': 0.16; 'received:io': 0.16; 'received:psf.io': 0.16; 'wrote:': 0.16; 'string': 0.17; 'result,': 0.18; '2015': 0.20; 'cc:2**0': 0.20; 'cc:addr:python.org': 0.20; 'written': 0.24; 'header:In-Reply- To:1': 0.24; 'subject:list': 0.26; 'sense': 0.26; 'define': 0.27; 'order.': 0.27; 'message-id:@mail.gmail.com': 0.27; '14,': 0.27; 'function': 0.28; 'values': 0.28; '13,': 0.29; 'dictionary': 0.29; 'doing?': 0.29; 'entry': 0.31; '"the': 0.32; 'tue,': 0.34; 'list': 0.34; 'received:google.com': 0.35; 'could': 0.35; 'i.e.': 0.35; 'nov': 0.35; 'but': 0.36; 'received:209.85': 0.36; 'pm,': 0.36; 'subject:: ': 0.37; 'thanks': 0.37; 'received:209': 0.38; 'mean': 0.38; 'does': 0.39; 'subject:from': 0.39; 'takes': 0.39; 'results': 0.66; 'chrisa': 0.84; 'dict.': 0.84; 'to:none': 0.91 DKIM-Signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:in-reply-to:references:date:message-id:subject:from:cc :content-type; bh=KPmvvxy8388fZri08f7CEK5+7Qmxvqygmk66tYvHrWU=; b=MrHP51FPugSXoLANNycazFc4reDTzN/J6Bsoqnf6fuGaY5DswsExo08m0dmzev/mqX cs9SeRIK6cM6+TyeGwgndNvp9Whthnc/qg3qCxJvqcoqkGLnLAlIEmmNp5WYu2zeqIju vP3M30gPVF8f8Zz0739sGnVOGBeL++sVDfWC8q9nmr57CiSESMWSFhCcMWBCTMl3db9u dzz+Ah2iuuJyY7iBugvAj4As4M8QP/uIS71JqjoBciH0EuDXNzDLZ2QwrNYJG54M5ka1 hzECYGrt/aZEjJrG4ICNzj+4s6+XQYJ4NN4KY3uNs+MztnYP14eUKSosDCUljWIEPeW8 fTIg== X-Received: by 10.107.16.84 with SMTP id y81mr27328115ioi.19.1448360059933; Tue, 24 Nov 2015 02:14:19 -0800 (PST) In-Reply-To: <133829df-f57f-442f-9dbf-b22b22f656ae@googlegroups.com> X-BeenThere: python-list@python.org X-Mailman-Version: 2.1.20+ Precedence: list List-Id: General discussion list for the Python programming language List-Unsubscribe: , List-Archive: List-Post: List-Help: List-Subscribe: , Xref: csiph.com comp.lang.python:99306 On Tue, Nov 24, 2015 at 9:04 PM, Cai Gengyang wrote: > Here's a dictionary with 3 values : > > results = { > "gengyang": 14, > "ensheng": 13, > "jordan": 12 > } > > How do I define a function that takes the last of the 3 items in that list and returns Jordan's results i.e. (12) ? > > Thanks a lot ! If you want Jordan's result, that's easy: result["jordan"] But there's no concept of "the last" entry in a dict. They don't have an order. Do you mean "the entry with the greatest key"? That could be written thus: result[max(result)] because max(result) is the string "jordan". Does either of those make sense for what you're doing? ChrisA