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Date: Tue, 23 Apr 2013 12:43:07 +0530
Subject: Re: Running simultaneuos "FOR" loops
From: inshu chauhan <insideshoes@gmail.com>
Cc: "python-list@python.org" <python-list@python.org>
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This statement is giving me the following error

Statement:
for p, k, j in zip(sorted(segments.iterkeys(), class_count.iterkeys(),
pixel_count.iterkeys())):

Error:
Traceback (most recent call last):
  File "C:\Users\inshu\Desktop\Training_segs_trial2.py", line 170, in
<module>
    access_segments(segimage, data)
  File "C:\Users\inshu\Desktop\Training_segs_trial2.py", line 147, in
access_segments
    for p, k, j in zip(sorted(segments.iterkeys(), class_count.iterkeys(),
pixel_count.iterkeys())):
TypeError: 'dictionary-keyiterator' object is not callable





On Tue, Apr 23, 2013 at 12:33 PM, inshu chauhan <insideshoes@gmail.com>wrote:

> zip isn't doing the required
>
>
> On Tue, Apr 23, 2013 at 12:28 PM, inshu chauhan <insideshoes@gmail.com>wrote:
>
>> Yes Simultaneously means all three running at the same time, I looked up
>> zip just now, but will it not disturb my dictionaries ?
>> And yes the dictionaries have same number of keys.
>>
>> thanks
>>
>>
>> On Tue, Apr 23, 2013 at 12:16 PM, Chris Angelico <rosuav@gmail.com>wrote:
>>
>>> On Tue, Apr 23, 2013 at 4:40 PM, inshu chauhan <insideshoes@gmail.com>
>>> wrote:
>>> > i have to implement the below line in one of my code:
>>> >
>>> > for  p in sorted(segments.iterkeys()) and for k in
>>> > sorted(class_count.iterkeys()) and for j in
>>> sorted(pixel_count.iterkeys()):
>>> >
>>> > Its giving me a syntax error which is obvious, but how can I make all
>>> three
>>> > for loop run simultaneously or any other way to do this simultaneous
>>> work
>>> > ???
>>>
>>> Define simultaneously. Do the three dictionaries have the same number
>>> of keys? If so, look up zip() or itertools.izip; if not, you may have
>>> to more clearly define "simultaneous".
>>>
>>> ChrisA
>>> --
>>> http://mail.python.org/mailman/listinfo/python-list
>>>
>>
>>
>

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Content-Type: text/html; charset=ISO-8859-1
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<div dir=3D"ltr">This statement is giving me the following error<div><br></=
div><div>Statement:<br><div>for p, k, j in zip(sorted(segments.iterkeys(), =
class_count.iterkeys(), pixel_count.iterkeys())):<br></div></div><div><br>
</div><div style>Error:=A0</div><div style><div>Traceback (most recent call=
 last):</div><div>=A0 File &quot;C:\Users\inshu\Desktop\Training_segs_trial=
2.py&quot;, line 170, in &lt;module&gt;</div><div>=A0 =A0 access_segments(s=
egimage, data)</div>
<div>=A0 File &quot;C:\Users\inshu\Desktop\Training_segs_trial2.py&quot;, l=
ine 147, in access_segments</div><div>=A0 =A0 for p, k, j in zip(sorted(seg=
ments.iterkeys(), class_count.iterkeys(), pixel_count.iterkeys())):</div><d=
iv>
TypeError: &#39;dictionary-keyiterator&#39; object is not callable</div><di=
v><br></div><div><br></div><div><br></div></div></div><div class=3D"gmail_e=
xtra"><br><br><div class=3D"gmail_quote">On Tue, Apr 23, 2013 at 12:33 PM, =
inshu chauhan <span dir=3D"ltr">&lt;<a href=3D"mailto:insideshoes@gmail.com=
" target=3D"_blank">insideshoes@gmail.com</a>&gt;</span> wrote:<br>
<blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1p=
x #ccc solid;padding-left:1ex"><div dir=3D"ltr">zip isn&#39;t doing the req=
uired=A0</div><div class=3D"HOEnZb"><div class=3D"h5"><div class=3D"gmail_e=
xtra"><br>
<br><div class=3D"gmail_quote">On Tue, Apr 23, 2013 at 12:28 PM, inshu chau=
han <span dir=3D"ltr">&lt;<a href=3D"mailto:insideshoes@gmail.com" target=
=3D"_blank">insideshoes@gmail.com</a>&gt;</span> wrote:<br>
<blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1p=
x #ccc solid;padding-left:1ex"><div dir=3D"ltr">Yes Simultaneously means al=
l three running at the same time, I looked up zip just now, but will it not=
 disturb my dictionaries ?=A0<div>

And yes the dictionaries have same number of keys.=A0</div><div>
<br></div><div>thanks=A0</div></div><div><div><div class=3D"gmail_extra"><b=
r><br><div class=3D"gmail_quote">On Tue, Apr 23, 2013 at 12:16 PM, Chris An=
gelico <span dir=3D"ltr">&lt;<a href=3D"mailto:rosuav@gmail.com" target=3D"=
_blank">rosuav@gmail.com</a>&gt;</span> wrote:<br>


<blockquote class=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1p=
x #ccc solid;padding-left:1ex"><div><div>On Tue, Apr 23, 2013 at 4:40 PM, i=
nshu chauhan &lt;<a href=3D"mailto:insideshoes@gmail.com" target=3D"_blank"=
>insideshoes@gmail.com</a>&gt; wrote:<br>



&gt; i have to implement the below line in one of my code:<br>
&gt;<br>
&gt; for =A0p in sorted(segments.iterkeys()) and for k in<br>
&gt; sorted(class_count.iterkeys()) and for j in sorted(pixel_count.iterkey=
s()):<br>
&gt;<br>
&gt; Its giving me a syntax error which is obvious, but how can I make all =
three<br>
&gt; for loop run simultaneously or any other way to do this simultaneous w=
ork<br>
&gt; ???<br>
<br>
</div></div>Define simultaneously. Do the three dictionaries have the same =
number<br>
of keys? If so, look up zip() or itertools.izip; if not, you may have<br>
to more clearly define &quot;simultaneous&quot;.<br>
<br>
ChrisA<br>
<span><font color=3D"#888888">--<br>
<a href=3D"http://mail.python.org/mailman/listinfo/python-list" target=3D"_=
blank">http://mail.python.org/mailman/listinfo/python-list</a><br>
</font></span></blockquote></div><br></div>
</div></div></blockquote></div><br></div>
</div></div></blockquote></div><br></div>

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