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Xref: csiph.com comp.lang.python:70724

On 2014-04-29 18:37, wxjmfauth@gmail.com wrote:
> Let see how Python is ready for the next Unicode version
> (Unicode 7.0.0.Beta).
>
>
>>>> timeit.repeat("(x*1000 + y)[:-1]", setup="x = 'abc'; y = 'z'")
> [1.4027834829454946, 1.38714224331963, 1.3822586635296261]
>>>> timeit.repeat("(x*1000 + y)[:-1]", setup="x = 'abc'; y = '\u0fce'")
> [5.462776291480395, 5.4479432055423445, 5.447874284053398]
>>>>
>>>>
>>>> # more interesting
>>>> timeit.repeat("(x*1000 + y)[:-1]",\
> ...     setup="x = 'abc'.encode('utf-8'); y = '\u0fce'.encode('utf-8')")
> [1.3496489533188765, 1.328654286266783, 1.3300913977710707]
>>>>
>
Although the third example is the fastest, it's also the wrong way to
handle Unicode:

 >>> x = 'abc'.encode('utf-8'); y = '\u0fce'.encode('utf-8')
 >>> t = (x*1000 + y)[:-1].decode('utf-8')
Traceback (most recent call last):
   File "<stdin>", line 1, in <module>
UnicodeDecodeError: 'utf-8' codec can't decode bytes in position 
3000-3001: unex
pected end of data

> Note 1:  "lookup" is not the problem.
>
> Note 2: From Unicode.org : "[...] We strongly encourage [...] and test
> them with their programs [...]"
>
> -> Done.
>
> jmf
>