Path: csiph.com!usenet.pasdenom.info!aioe.org!news.stack.nl!newsfeed.xs4all.nl!newsfeed6.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail
Return-Path: <python-python-list@m.gmane.org>
X-Original-To: python-list@python.org
Delivered-To: python-list@mail.python.org
X-Spam-Status: OK 0.012
X-Spam-Evidence: '*H*': 0.98; '*S*': 0.00; 'received:80.91': 0.09; 'received:80.91.229': 0.09; 'received:gmane.org': 0.09; 'received:list': 0.09; 'dictionaries': 0.16; 'keys.': 0.16; 'received:80.91.229.3': 0.16; 'received:plane.gmane.org': 0.16; 'keys': 0.22; 'header:User-Agent:1': 0.26; 'header:X-Complaints- To:1': 0.28; 'values.': 0.33; 'to:addr:python-list': 0.33; 'list': 0.35; 'received:org': 0.36; 'to:addr:python.org': 0.39; 'where': 0.40; 'header:Received:5': 0.40; 'received:139': 0.84
X-Injected-Via-Gmane: http://gmane.org/
To: python-list@python.org
From: Neal Becker <ndbecker2@gmail.com>
Subject: A little morning puzzle
Date: Wed, 19 Sep 2012 07:17 -0400
Mime-Version: 1.0
Content-Type: text/plain; charset="ISO-8859-1"
Content-Transfer-Encoding: 7Bit
X-Gmane-NNTP-Posting-Host: 139.85.237.19
User-Agent: KNode/4.9.1
X-BeenThere: python-list@python.org
X-Mailman-Version: 2.1.15
Precedence: list
List-Id: General discussion list for the Python programming language <python-list.python.org>
List-Unsubscribe: <http://mail.python.org/mailman/options/python-list>, <mailto:python-list-request@python.org?subject=unsubscribe>
List-Archive: <http://mail.python.org/pipermail/python-list/>
List-Post: <mailto:python-list@python.org>
List-Help: <mailto:python-list-request@python.org?subject=help>
List-Subscribe: <http://mail.python.org/mailman/listinfo/python-list>, <mailto:python-list-request@python.org?subject=subscribe>
Newsgroups: comp.lang.python
Message-ID: <mailman.907.1348053436.27098.python-list@python.org>
Lines: 3
NNTP-Posting-Host: 2001:888:2000:d::a6
X-Trace: 1348053436 news.xs4all.nl 6963 [2001:888:2000:d::a6]:39024
X-Complaints-To: abuse@xs4all.nl
Xref: csiph.com comp.lang.python:29479

I have a list of dictionaries.  They all have the same keys.  I want to find the 
set of keys where all the dictionaries have the same values.  Suggestions?