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Date: Sun, 24 Apr 2011 15:41:42 -0700
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Subject: Re: Pls chk my login script
From: Chris Rebert <clp2@rebertia.com>
To: nusrath ahmed <nusrathahmed@yahoo.com>
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Xref: x330-a1.tempe.blueboxinc.net comp.lang.python:3965

On Sun, Apr 24, 2011 at 3:05 PM, nusrath ahmed <nusrathahmed@yahoo.com> wro=
te:
> I have written a python script for logging into a website. My script pull=
s
> up a browser page but does not log me in. Can any one suggest if I i am
> wrong in nay way,though the script is correct I am sure
>
> My script is as below
>
>
> *********************************************
> import cookielib
> import urllib
> import urllib2
> import httplib
>
> if __name__ =3D=3D '__main__':
> =C2=A0=C2=A0=C2=A0 urlLogin =3D 'http://www.gmail.com'
>
> =C2=A0=C2=A0=C2=A0 id=C2=A0=C2=A0=C2=A0 =3D 'u2'
> =C2=A0=C2=A0=C2=A0 passw =3D 'p2'
>
> =C2=A0=C2=A0=C2=A0 fieldId=C2=A0=C2=A0 =3D 'username'
> =C2=A0=C2=A0=C2=A0 fieldPass =3D 'password'
>
> =C2=A0=C2=A0=C2=A0 cj =3D cookielib.CookieJar()
> =C2=A0=C2=A0=C2=A0 data =3D urllib.urlencode({fieldId:id, fieldPass:passw=
})
<snip>
> =C2=A0=C2=A0=C2=A0 usock =3D opener.open(urlLogin,=C2=A0 data)

You're supposed to submit to the "action" URL specified by the form,
not the URL the form itself is on (unless they happen to be the same).

Also, please don't make a whole new thread just to post a follow-up reply.

Regards,
Chris